Completed Design - 1

[satish-paraddi]

No description provided.

[super30admin]

Design HashSet (design_1.py)

[Constructive feedback for this student]

VERDICT: PASS

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Min Stack (problem-1.py)

Excellent work! Your solution correctly implements the MinStack with O(1) time complexity using the two-stack approach. The logic is sound and handles all edge cases properly.

Strengths:

1. Correct algorithm: The two-stack approach is a classic and efficient way to solve this problem.
2. Clean code: Your code is readable and well-structured.
3. Pythonic style: Good use of float('inf') for the initial minimum value.
4. Correct condition: Using >= in the push condition is actually correct - it ensures that when you pop a value equal to the current minimum, you properly restore the previous minimum.

Suggestions for improvement:

1. Add docstrings: Consider adding docstrings to each method to explain what they do.
2. Type hints: Adding type hints (e.g., def push(self, value: int) -> None:) would improve code clarity and IDE support.
3. Variable naming: The parameter name value is fine, but you could consider matching the problem's val for consistency with the problem statement.

Here's an enhanced version with these improvements:

class MinStack:
    def __init__(self):
        """
        Initialize your data structure here.
        """
        self.st = []
        self.min_st = []
        self.min = float('inf')
    
    def push(self, val: int) -> None:
        """
        Push element val onto stack.
        """
        if self.min >= val:
            self.min_st.append(self.min)
            self.min = val
        self.st.append(val)
    
    def pop(self) -> None:
        """
        Removes the element on top of the stack.
        """
        if self.st.pop() == self.min:
            self.min = self.min_st.pop()
    
    def top(self) -> int:
        """
        Get the top element.
        """
        return self.st[-1]
    
    def getMin(self) -> int:
        """
        Retrieve the minimum element in the stack.
        """
        return self.min

Overall, your solution is correct, efficient, and well-written. Keep up the good work!

VERDICT: PASS