Lab done

lab sakila.sql

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+USE sakila;
+
+-- Display all available tables in the Sakila database 
+show tables;
+
+-- Retrieve all the data from the tables actor, film and customer 
+SELECT * FROM actor, film, customer; 
+
+-- Retrieve the following columns from their respective tables:
+	#3.1 Titles of all films from the film table
+    SELECT title FROM film;
+
+	#3.2 List of languages used in films, with the column aliased as language from the language table
+    SELECT name AS language FROM language;
+
+	#3.3 List of first names of all employees from the staff table 
+    SELECT first_name FROM staff; 
+
+-- Retrieve unique release years. 
+SELECT DISTINCT release_year FROM film; 
+
+-- Counting records for database insights:
+	# 5.1 Determine the number of stores that the company has. 2 stores 
+    SELECT COUNT(*) FROM store;
+
+    # 5.2 Determine the number of employees that the company has. 2 employees 
+    SELECT COUNT(*) FROM staff; 
+
+	# 5.3 Determine how many films are available for rent and how many have been rented.
+    SELECT * FROM rental LIMIT 20; 
+
+    SELECT COUNT(*) FROM inventory; -- 4581 films available for rent 
+    SELECT COUNT(*) FROM rental; # 16044 rental transactions 
+
+    SELECT DISTINCT COUNT(*) FROM rental;
+
+	# 5.4 Determine the number of distinct last names of the actors in the database.
+	SELECT  COUNT(DISTINCT last_name) FROM actor; 121 unique last names 
+
+-- Retrieve the 10 longest films.
+SELECT * FROM film;
+
+SELECT film_id, title, description, length FROM film 
+ORDER BY length DESC
+LIMIT 10;
+
+-- Use filtering techniques in order to:
+	# 7.1 Retrieve all actors with the first name "SCARLETT".
+	SELECT * FROM actor 
+    WHERE first_name = "SCARLETT"
+    ORDER BY first_name; 
+
+-- 7.2 Retrieve all movies that have ARMAGEDDON in their title and have a duration longer than 100 minutes.
+SELECT * FROM film 
+WHERE title LIKE "%ARMAGEDDON%" AND length > 100; 
+
+-- 7.3 Determine the number of films that include Behind the Scenes content
+SELECT special_features FROM film;  
+
+SELECT COUNT(*) FROM film 
+WHERE special_features LIKE "%Behind the Scenes%";