diff --git a/Lab_SQL_basic_queries.sql b/Lab_SQL_basic_queries.sql
new file mode 100644
index 0000000..71214e2
--- /dev/null
+++ b/Lab_SQL_basic_queries.sql
@@ -0,0 +1,45 @@
+USE sakila;
+-- Display all tables:
+SHOW TABLES;
+-- Retrieve all the data from the tables actor, film and customer
+SELECT * FROM actor;
+SELECT * FROM film;
+SELECT * FROM customer;
+-- Retrieve the following columns from their respective tables
+-- 3.1 Titles of all films from the film table
+-- 3.2 List of languages used in films, with the column aliased as language from the language table
+-- 3.3 List of first names of all employees from the staff table
+SELECT title FROM film;
+SELECT name AS language FROM language;
+SELECT first_name FROM staff;
+-- Retrieve unique release years
+SELECT DISTINCT release_year FROM film;
+-- Counting records for database insights:
+-- 5.1 Determine the number of stores that the company has.
+-- 5.2 Determine the number of employees that the company has.
+-- 5.3 Determine how many films are available for rent and how many have been rented.
+-- 5.4 Determine the number of distinct last names of the actors in the database.
+SELECT COUNT(DISTINCT store_id) FROM store;
+SELECT COUNT(DISTINCT staff_id) FROM staff;
+SELECT COUNT(DISTINCT film_id) FROM inventory;
+SELECT COUNT(DISTINCT inventory.film_id)
+FROM rental
+JOIN inventory
+ON rental.inventory_id = inventory.inventory_id;
+SELECT COUNT(DISTINCT last_name) FROM actor;
+-- Retrieve the 10 longest films
+SELECT title, length FROM film
+ORDER BY length DESC LIMIT 10;
+-- Use filtering techniques in order to:
+-- 7.1 Retrieve all actors with the first name "SCARLETT".
+SELECT first_name, last_name FROM actor
+WHERE first_name = "SCARLETT";
+-- 7.2 Retrieve all movies that have ARMAGEDDON in their title and have a duration longer than 100 minutes.
+-- Hint: use LIKE operator. More information here.
+-- 7.3 Determine the number of films that include Behind the Scenes content
+SELECT title, length FROM film
+WHERE title LIKE "%ARMAGEDDON%" AND length > 100;
+SELECT COUNT(title) FROM film
+WHERE special_features LIKE "%Behind the Scenes%";
+
+